## Help again

This is the place for queries that don't fit in any of the other categories.

### Help again

Suppose Sam is trying to walk from his house to his friend's house, which is 8 metres away. First he must get half way there (4 metres), then a quarter (2 metres) (as this is half of what remains to travel), then an eighth (1 metre), then a sixteenth (0.5 metres) etc etc. How can he ever reach his destination?

Implement a program that asks the user for a distance and a number of steps, and prints out the remaining distance assuming the person travels in this manner.

Your program should work like this:
Enter a distance: 8
Number of steps: 5
Distance remaining = 0.25 m

And this:
Enter a distance: 2.5
Number of steps: 4
Distance remaining = 0.15625 m

my attempt is

Code: Select all
`a = float(input('Enter a distance: '))b = int(input("Number of steps: "))print("Distance remaining =", (a / ( 2 ^ b )), "m")`

but i don't know what i was meant to do in the 3rd line.

Also a step is a single movement (which might be many meters). Try to think of it as logical steps in a process, rather than a physical walking step.

So step one is 4 meters, step 2 is 2 meters, etc, etc.
el_manu

Posts: 87
Joined: Mon Aug 19, 2013 8:30 am

### Re: Help again

Code: Select all
`m = "m"a = float(input('Enter a distance: '))b = int(input("Number of steps: "))print("Distance remaining =", (a / 2 ** b), m)`

figured it out don't worry
el_manu

Posts: 87
Joined: Mon Aug 19, 2013 8:30 am

### Re: Help again

For this problem you need to write a for loop that loops over the number of steps you take. Each iteration divide the remaining distance by 2. I suggest you use the augmented assignment operator "/=".

Take another shot with a loop and we'll work from there.

-Mek

Edit:
Your answer is indeed correct; however your instructor was probably aiming at you using a for loop. Anyway, nice work.
Code: Select all
`for step in range(steps):    distance /= 2.0`
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Mekire

Posts: 1711
Joined: Thu Feb 07, 2013 11:33 pm
Location: Tucson, Arizona

### Re: Help again

i think he probably was looking for a loop. Thanks for telling me that.
el_manu

Posts: 87
Joined: Mon Aug 19, 2013 8:30 am

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